5/b^2-4

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Solution for 5/b^2-4 equation: 


D( b )

b^2 = 0

b^2 = 0

b^2 = 0

1*b^2 = 0 // : 1

b^2 = 0

b = 0

b in (-oo:0) U (0:+oo)

5/(b^2)-4 = 0

5*b^-2 = 4 // : 5

b^-2 = 4/5

-2 < 0

1/(b^2) = 4/5 // * b^2

1 = 4/5*b^2 // : 4/5

5/4 = b^2

b^2 = 5/4 // ^ 1/2

abs(b) = (5/4)^(1/2)

b = (5/4)^(1/2) or b = -(5/4)^(1/2)

b in { (5/4)^(1/2), -(5/4)^(1/2) }

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